PHP调用webservice,返回字符串但取不到返回值

Question

PHP调用webservice，但取不到返回值，在网页上直接获取是可以拿到返回值的。

获取返回值的方法如下：

ini_set("soap.wsdl_cache_enabled",0);

function getSoapData($cardNo){    

    echo '##########################,';
    echo $cardNo;
    try {
        // 示例webservice地址.
        $client = new SoapClient ( "http://soap.org/wsdl?", array (
                'encoding' => 'UTF-8' 
        ) );
        $strinfo = $client-> GetOpenID( array (
                'CardNo'=>$cardNo
        ) );
        echo ',##########################'.$client->GetOpenID($cardNo);
    } catch ( Exception $e ) {
        echo 'ERR\n\n\n';
        Think\Log::record ( $e, 'ERR' );
    }
    return $strinfo;
}

网页上的返回值是：

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:s="http://www.w3.org/2001/XMLSchema">
    <SOAP-ENV:Body>
        <GetOpenIDResponse xmlns="http://www.xxxxxxxx.cn">
            <GetOpenIDResult>fdlsakfjsdlafsdkllfk02943ielkdsjfalsdk12878</GetOpenIDResult>
        </GetOpenIDResponse>
    </SOAP-ENV:Body>
</SOAP-ENV:Envelope>

请问该怎么才能取到返回值？？谢谢.

Answer 1

    $client = new SoapClient($host, array(
        'trace' => true,
        'cache_wsdl' => WSDL_CACHE_BOTH,
    ));
    $functionName = 'funcname';
    $response = $client->__soapCall($functionName, array(
        $functionName => array('in0' => $params),
    ));

确认一下你的soap Server地址