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HarmonyOS
《jquery 基础教程（第四版）》第二章后面的练习：
(4) 挑战：选择包含链接（）的所有列表项（<li>元素），为每个选中的列表项的同辈列
表项元素添加afterlink类；
HTML：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Selected Shakespeare Plays</title>
<link rel="stylesheet" href="02.css" type="text/css" />
<script src="jquery.js"></script>
<script src="02.js"></script>
</head>
<body>
<div id="container">
<h2>Selected Shakespeare Plays</h2>
<ul id="selected-plays" class="clear-after">
<li>Comedies
<ul>
<li><a href="/asyoulikeit/">As You Like It</a></li>
<li>All's Well That Ends Well</li>
<li>A Midsummer Night's Dream</li>
<li>Twelfth Night</li>
</ul>
</li>
<li>Tragedies
<ul>
<li><a href="hamlet.pdf">Hamlet</a></li>
<li>Macbeth</li>
<li>Romeo and Juliet</li>
</ul>
</li>
<li>Histories
<ul>
<li>Henry IV (<a href="mailto:henryiv@king.co.uk">email</a>)
<ul>
<li>Part I</li>
<li>Part II</li>
</ul>
</li>
<li><a href="http://www.shakespeare.co.uk/henryv.htm">Henry V</a></li>
<li>Richard II</li>
</ul>
</li>
</ul>
<h2>Shakespeare's Plays</h2>
<table>
<tr>
<td>As You Like It</td>
<td>Comedy</td>
<td></td>
</tr>
<tr>
<td>All's Well that Ends Well</td>
<td>Comedy</td>
<td>1601</td>
</tr>
<tr>
<td>Hamlet</td>
<td>Tragedy</td>
<td>1604</td>
</tr>
<tr>
<td>Macbeth</td>
<td>Tragedy</td>
<td>1606</td>
</tr>
<tr>
<td>Romeo and Juliet</td>
<td>Tragedy</td>
<td>1595</td>
</tr>
<tr>
<td>Henry IV, Part I</td>
<td>History</td>
<td>1596</td>
</tr>
<tr>
<td>Henry V</td>
<td>History</td>
<td>1599</td>
</tr>
</table>
<h2>Shakespeare's Sonnets</h2>
<table>
<tr>
<td>The Fair Youth</td>
<td>1–126</td>
</tr>
<tr>
<td>The Dark Lady</td>
<td>127–152</td>
</tr>
<tr>
<td>The Rival Poet</td>
<td>78–86</td>
</tr>
</table>
</div>
</body>
</html>
jS：
$('li').has('a').siblings().addClass('afterlink');为什么不包含的<li>也是配到了？
因为has 不单单可以拿到子元素，还可以拿到父元素。你的li上面还有li
参考http://www.w3school.com.cn/jq...