用JS将数组里满足条件的内容筛选出来

Question

如题。比如一个数组是【1,6,3,5,0,40,35,1,65，2,30,19】.然后如果我想要 大于3小于30 的内容并且输出出来，应该怎么办？

Answer 1

es6写法：

[1,6,3,5,0,40,35,1,65,2,30,19].filter((item)=>{return item>3&&item<30});

[6, 5, 19]

es5写法：

[1,6,3,5,0,40,35,1,65,2,30,19].filter(function(item){
    return item>3&&item<30;
});

Answer 2

循环遍历一下吧

Answer 3

var arr = [1,6,3,5,0,40,35,1,65，2,30,19];
for(var i = 0; i < arr.length; i++) {
    if(arr[i] > 3 && arr[i] < 30) {
        console.log(arr[i]);
    }
}

终于会一题了..............

Answer 4

let a = [1, 6, 3, 5, 0, 40, 35, 1, 65, 2, 30, 19]
let b = a.filter( val => val > 0 && val < 30 )
//b = [1, 6, 3, 5, 1, 2, 19]

Answer 5

   var arr = [1,6,3,5,0,40,35,1,65,2,30,19];
    var newArr= [];
    arr.forEach(function(value,index){
        if(value>=3&&value<=30){
           newArr.push(value)
        }
    })
    console.log(newArr)

Answer 6

var arr=[1,4,6,8,3,9,3,90];
var rel=arr.filter(function (i) {
    return i>6&&i<10;
})
console.log(rel)//[8,9]