js如何获取数组中指定个数的几个最大值

Question

数组如下:

var arr = [1,5,3,2,10,15]

如何得到3个或N个最大值得数组

arr2 = [5,10,15]

Answer 1

var arr = [1,5,3,2,10,15];
  function maxarr(arr,len){
      var max = [];
    arr.sort(function(a,b){
       return a-b;
   });
   for(var i=0;i<len;i++){
       max.push(arr.pop());
   }
   return max.reverse();
  }

   console.log(maxarr(arr,4));

Answer 2

let largest = (arr, n) => arr.sort((a,b) => a < b).slice(0, n);

let arr = [1,5,3,2,10,15];
console.log(largest(arr, 3));

Answer 3

冒泡排序，然后取前几个

Answer 4

按照规则排序后直接使用slice方法拉取前n项

Answer 5

试试这个，可以获取最大最小，并且可以自定义

function minOrMaxsInArray(array, length, compare) {

    let result = {};

    if (array == null || !(array instanceof Array)) {
        return result;
    }
    // 默认长度为数组的长度
    length = length || array.length;
    // 数组比较方法
    compare = compare || function (a, b) {
            return a - b;
        };

    // 进行排序
    array.sort(compare);

    result = {
        1: array.slice(0, length),
        2: array.reverse().slice(0, length)
    };

    return function (type) {
        return result[type] || [];
    }

}

获取普通数组最大 || 最小集合：

let arr = [1, 5, 3, 2, 10, 15];
console.log(minOrMaxsInArray(arr, 4)(1));
console.log(minOrMaxsInArray(arr, 4)(2));

获取对象数组的最大 || 最小集合

let arr2 = [{id: 1}, {id: 3}, {id: 4}, {id: 9}, {id: 12}, {id: 199}];
console.log(minOrMaxsInArray(arr2, 4, (a, b) => (a.id - b.id))(1));