php执行sql返回不了结果

Question

报错Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, string given in

Answer 1

mysql_fetch_array()第一个参数是mysql_query所查询出来的结果。
多看看文档吧。

<?php
$con = mysql_connect("localhost", "hello", "321");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

$db_selected = mysql_select_db("test_db",$con);
$sql = "SELECT * from Person WHERE Lastname='Adams'";
$result = mysql_query($sql,$con);
print_r(mysql_fetch_array($result));

mysql_close($con);
?>