JSON 数据拆分

Question

这是在数据提交时遇到的问题。

我准备的数据结构是这样的：

    {
        "path": "test",
        "clients": [
            {
                "client": "1.2.2.2;1.1.1.1",
                "Access_Type": 2,
                "name": "test_01"
            },
            {
                "client": "1.2.2.4;1.1.1.4",
                "Access_Type": 1,
                "name": "test_02"
            },
            {
                "client": "1.3.3.3",
                "Access_Type": 1,
                "name": "test_03"
            }
        ]
    }

然而我在提交时需要的数据结构，却是这样的：

    {
        "path": "test",
        "clients": [
            {
                "client": "1.2.2.2",
                "Access_Type": 2,
                "name": "test_01"
            },
            {
                "client": "1.1.1.1",
                "Access_Type": 2,
                "name": "test_01"
            },
            {
                "client": "1.2.2.4",
                "Access_Type": 1,
                "name": "test_02"
            },
            {
                "client": "1.1.1.4",
                "Access_Type": 1,
                "name": "test_02"
            },
            {
                "client": "1.3.3.3",
                "Access_Type": 1,
                "name": "test_03"
            }
        ]
    }

注：client对应的字段，如果是多条并以“；”分隔，则做拆分处理，单条则不处理。

那么如何将数据修改为提交需要的结构？
而对于这种JSON数据结构的拆分，大家有什么解决方案，希望指教一下！

Answer 1

上面是需要的还是下面是需要的。。。

Answer 2

let json =  {
    "path": "test",
    "clients": [
        {
            "client": "1.2.2.2;1.1.1.1",
            "Access_Type": 2,
            "name": "test_01"
        },
        {
            "client": "1.2.2.4;1.1.1.4",
            "Access_Type": 1,
            "name": "test_02"
        },
        {
            "client": "1.3.3.3",
            "Access_Type": 1,
            "name": "test_03"
        }
    ]
}
let clients = [];
json.clients.map(ele1=>{
    let {client,Access_Type,name} = ele1;
    client.split(';').map(ele2=>{
        clients.push({client:ele2,Access_Type,name})
    })
})
json['clients']= clients;

Answer 3

    var bbb = {
        "path": "test",
        "clients":[]
    };
     for(var i in aa.clients){
        var splitarr = aa.clients[i].client.split(";");
            for(var j=0;j<splitarr.length;j++){
                bbb["clients"].push({
                    "client":splitarr[j],
                    "Access_Type":aa.clients[i].Access_Type,
                    "name":aa.clients[i].name
                })
            }       
    }
    console.log(bbb);

Answer 4

"code": 0,

"message": "success",
"data": [{
    "product_id": "1",
    "name": "绝缘手套",
    "product_catalogue_id": "1",
    "current_num": "0",
    "need_display_num": "4",
    "product_detail_id": "1",
    "isnormal": "1",
    "tag": "不过期",
    "tag_no": "#1-1,#1-2",
    "date_fit": "-30",
    "inspect_interval": "6",
    "material_des": "鼓起来的视频+好模型",
    "img_path": "jueyuanshoutao",
    "video_path": "shoutao.ogv",
    "model_path": "Mo\/jueyuanshoutao",
    "scene": null,
    "name_eng": "shoutao",
    "isneed": "1"
},

这个怎么拆分