js字符串处理，大家有什么好的答案？

西树先森

7.1k22040

发布于
2017-12-30

输入字符串 aaaaaabbbbbccccddac
输出 a6b5c4d2a1c1

用JavaScript 语言
或其他语言都可以

javascript

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4 个回答

得票最新

CRIMX

9.1k3720

发布于
2017-12-30

✓ 已被采纳

Here comes oneliner

const countSuccession = s => s.match(/(.)\1*/g).reduce((r, x) => r + x[0] + x.length, '')

console.log(countSuccession('aaaaaabbbbbccccddac'))

张京

13.4k61442

发布于
2017-12-30

var result = '';
'aaaaaabbbbbccccddac'.match(/(.)\1*/g).map(function (item) {
  result += item[0] + item.length;
});
console.log(result);

西树先森

7.1k22040

发布于
2017-12-30

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <meta http-equiv="X-UA-Compatible" content="ie=edge">
    <title>Document</title>
</head>
<body>
    <script>

        var strr = 'aaaaaabbbbbccccddac';
        function handleStr(str) {
                var n = 1;
                var srtn = '';
                for (i = 0; i < str.length; i++) {
                    if (str[i] == str[i + 1]) {
                        n++;
                    } else {
                        srtn += str[i]+n;
                        n = 1;
                    }

                }
                console.log(srtn);
                return srtn;
            }

            handleStr(strr);
    </script>
</body>
</html>