medoo action 如何传参

Question

public static function create($title, $content, $label_ids){

    self::$db->action(function($db){
        $db->insert('articles', [
            'title' => $title,
            'content' => $content,
            'created_at' => self::$t,
            'updated_at' => self::$t,
            'created_date' => self::$t_date,
            'updated_date' => self::$t_date,
        ]);
        $article_id = $db->id();
        $data = [];
        foreach(explode(',', $label_ids) as $id){
            $data[] = [
                'article_id' => $article_id,
                'label_id' => $id,
                'created_at' => self::$t,
                'updated_at' => self::$t,
                'created_date' => self::$t_date,
                'updated_date' => self::$t_date,
            ];
        }
        $db->insert('article_labels', $data);
    });
}

如何将action外的变量传递进去

Answer 1

function (...) use (...) {...}

参考 PHP 文档：https://secure.php.net/manual...

Answer 2