跪求帮忙解析，急！！！

Question

1。第三方调用我的接口，带给我的xml文件，我用
$xmldata = file_get_contents("php://input")获取内容，得到如下格式的数据

'xml=%3C%3Fxml+version%3D%221.0%22+encoding%3D%22gbk%22+%3F%3E%253Ctask%253E%253Cuser%253E%253Coper%253Emod%253C%252Foper%253E%253Cid%253E14001420%2540private.gb.gov%253C%252Fid%253E%253Cname%253E%25E5%25A7%259A%25E8%25BF%259C%253C%252Fname%253E%253Cusertype%253EUT01%253C%252Fusertype%253E%253Cgrade%253E%25E5%2586%2585%25E9%2583%25A8%253C%252Fgrade%253E%253Cdname%253E%25E6%2596%2587%25E7%2594%25B5%25E5%25A4%2584%253C%252Fdname%253E%253Cdid%253E2021013100%2540private.gb.gov%253C%252Fdid%253E%253Cdorder%253E1%253C%252Fdorder%253E%253Cdcode%253E%253C%252Fdcode%253E%253Csexual%253E0%253C%252Fsexual%253E%253Cduty%253E%253C%252Fduty%253E%253Cpost%253E%253C%252Fpost%253E%253Caccount%253E14001420%253C%252Faccount%253E%253Cpassword%253E%253C%252Fpassword%253E%253Cmail%253E%253C%252Fmail%253E%253C%252Fuser%253E%253C%252Ftask%253E&trustId=DataPush_SPDB'

求大神帮忙看一下怎么解析成正常的xml格式，或者是PHP数组

Answer 1

确实如楼上所说 urlencode了两次.

<?php

$data = 'xml=%3C%3Fxml+version%3D%221.0%22+encoding%3D%22gbk%22+%3F%3E%253Ctask%253E%253Cuser%253E%253Coper%253Emod%253C%252Foper%253E%253Cid%253E14001420%2540private.gb.gov%253C%252Fid%253E%253Cname%253E%25E5%25A7%259A%25E8%25BF%259C%253C%252Fname%253E%253Cusertype%253EUT01%253C%252Fusertype%253E%253Cgrade%253E%25E5%2586%2585%25E9%2583%25A8%253C%252Fgrade%253E%253Cdname%253E%25E6%2596%2587%25E7%2594%25B5%25E5%25A4%2584%253C%252Fdname%253E%253Cdid%253E2021013100%2540private.gb.gov%253C%252Fdid%253E%253Cdorder%253E1%253C%252Fdorder%253E%253Cdcode%253E%253C%252Fdcode%253E%253Csexual%253E0%253C%252Fsexual%253E%253Cduty%253E%253C%252Fduty%253E%253Cpost%253E%253C%252Fpost%253E%253Caccount%253E14001420%253C%252Faccount%253E%253Cpassword%253E%253C%252Fpassword%253E%253Cmail%253E%253C%252Fmail%253E%253C%252Fuser%253E%253C%252Ftask%253E&trustId=DataPush_SPDB';

$data = urldecode($data);

parse_str($data, $r);

print_r($r["xml"]);

echo PHP_EOL;

输出

<?xml version="1.0" encoding="gbk" ?><task><user><oper>mod</oper><id>[e-mail]</id><name>姚远</name><usertype>UT01</usertype><grade>内部</grade><dname>文电处</dname><did>[e-mail]</did><dorder>1</dorder><dcode></dcode><sexual>0</sexual><duty></duty><post></post><account>14001420</account><password></password><mail></mail></user></task>

Answer 2

xml 这个参数的值，是被 urlencode 两次的东西。 php 不懂， Python 的话是用 urllib.unquote 就可以了。

>>> s = '''%3C%3Fxml+version%3D%221.0%22+encoding%3D%22gbk%22+%3F%3E%253Ctask%253E%253Cuser%253E%253Coper%253Emod%253C%252Foper%253E%253Cid%253E14001420%2540private.gb.gov%253C%252Fid%253E%253Cname%253E%25E5%25A7%259A%25E8%25BF%259C%253C%252Fname%253E%253Cusertype%253EUT01%253C%252Fusertype%253E%253Cgrade%253E%25E5%2586%2585%25E9%2583%25A8%253C%252Fgrade%253E%253Cdname%253E%25E6%2596%2587%25E7%2594%25B5%25E5%25A4%2584%253C%252Fdname%253E%253Cdid%253E2021013100%2540private.gb.gov%253C%252Fdid%253E%253Cdorder%253E1%253C%252Fdorder%253E%253Cdcode%253E%253C%252Fdcode%253E%253Csexual%253E0%253C%252Fsexual%253E%253Cduty%253E%253C%252Fduty%253E%253Cpost%253E%253C%252Fpost%253E%253Caccount%253E14001420%253C%252Faccount%253E%253Cpassword%253E%253C%252Fpassword%253E%253Cmail%253E%253C%252Fmail%253E%253C%252Fuser%253E%253C%252Ftask%253E'''
>>> import urllib
>>> urllib.unquote(s)
'<?xml+version="1.0"+encoding="gbk"+?>%3Ctask%3E%3Cuser%3E%3Coper%3Emod%3C%2Foper%3E%3Cid%3E14001420%40private.gb.gov%3C%2Fid%3E%3Cname%3E%E5%A7%9A%E8%BF%9C%3C%2Fname%3E%3Cusertype%3EUT01%3C%2Fusertype%3E%3Cgrade%3E%E5%86%85%E9%83%A8%3C%2Fgrade%3E%3Cdname%3E%E6%96%87%E7%94%B5%E5%A4%84%3C%2Fdname%3E%3Cdid%3E2021013100%40private.gb.gov%3C%2Fdid%3E%3Cdorder%3E1%3C%2Fdorder%3E%3Cdcode%3E%3C%2Fdcode%3E%3Csexual%3E0%3C%2Fsexual%3E%3Cduty%3E%3C%2Fduty%3E%3Cpost%3E%3C%2Fpost%3E%3Caccount%3E14001420%3C%2Faccount%3E%3Cpassword%3E%3C%2Fpassword%3E%3Cmail%3E%3C%2Fmail%3E%3C%2Fuser%3E%3C%2Ftask%3E'
>>> print urllib.unquote(s)
<?xml+version="1.0"+encoding="gbk"+?>%3Ctask%3E%3Cuser%3E%3Coper%3Emod%3C%2Foper%3E%3Cid%3E14001420%40private.gb.gov%3C%2Fid%3E%3Cname%3E%E5%A7%9A%E8%BF%9C%3C%2Fname%3E%3Cusertype%3EUT01%3C%2Fusertype%3E%3Cgrade%3E%E5%86%85%E9%83%A8%3C%2Fgrade%3E%3Cdname%3E%E6%96%87%E7%94%B5%E5%A4%84%3C%2Fdname%3E%3Cdid%3E2021013100%40private.gb.gov%3C%2Fdid%3E%3Cdorder%3E1%3C%2Fdorder%3E%3Cdcode%3E%3C%2Fdcode%3E%3Csexual%3E0%3C%2Fsexual%3E%3Cduty%3E%3C%2Fduty%3E%3Cpost%3E%3C%2Fpost%3E%3Caccount%3E14001420%3C%2Faccount%3E%3Cpassword%3E%3C%2Fpassword%3E%3Cmail%3E%3C%2Fmail%3E%3C%2Fuser%3E%3C%2Ftask%3E
>>> ss = '''%3Ctask%3E%3Cuser%3E%3Coper%3Emod%3C%2Foper%3E%3Cid%3E14001420%40private.gb.gov%3C%2Fid%3E%3Cname%3E%E5%A7%9A%E8%BF%9C%3C%2Fname%3E%3Cusertype%3EUT01%3C%2Fusertype%3E%3Cgrade%3E%E5%86%85%E9%83%A8%3C%2Fgrade%3E%3Cdname%3E%E6%96%87%E7%94%B5%E5%A4%84%3C%2Fdname%3E%3Cdid%3E2021013100%40private.gb.gov%3C%2Fdid%3E%3Cdorder%3E1%3C%2Fdorder%3E%3Cdcode%3E%3C%2Fdcode%3E%3Csexual%3E0%3C%2Fsexual%3E%3Cduty%3E%3C%2Fduty%3E%3Cpost%3E%3C%2Fpost%3E%3Caccount%3E14001420%3C%2Faccount%3E%3Cpassword%3E%3C%2Fpassword%3E%3Cmail%3E%3C%2Fmail%3E%3C%2Fuser%3E%3C%2Ftask%3E'''
>>> urllib.unquote(ss)
'<task><user><oper>mod</oper><id>[e-mail]</id><name>\xe5\xa7\x9a\xe8\xbf\x9c</name><usertype>UT01</usertype><grade>\xe5\x86\x85\xe9\x83\xa8</grade><dname>\xe6\x96\x87\xe7\x94\xb5\xe5\xa4\x84</dname><did>[e-mail]</did><dorder>1</dorder><dcode></dcode><sexual>0</sexual><duty></duty><post></post><account>14001420</account><password></password><mail></mail></user></task>'

Answer 3

urlencode() 解析两次就可以啦~