python多进程程序的执行次序

Question

这是我的程序：

import os,time
from multiprocessing import Process

def run_proc(name):
    print('child process %s (%s) running ...' %(name,os.getpid()))
    print('process will start'+name)
    time.sleep(5)
    print('end  '+name)

if __name__ == '__main__': 
    print('parent process %s.' %os.getppid())
    for i in range(5):
        p = Process(target=run_proc,args=(str(i),))
        p.start()

time python3 test1.py
parent process 4049.
child process 0 (7054) running ...
process will start0
child process 1 (7055) running ...
process will start1
child process 3 (7057) running ...
process will start3
child process 2 (7056) running ...
process will start2
child process 4 (7058) running ...
process will start4
end 0
end 1
end 3
end 2
end 4

real 0m5.099s
user 0m0.080s
sys 0m0.008s

为何执行结果不是
time python3 test1.py
parent process 4049.
child process 0 (7054) running ...
process will start0
child process 1 (7055) running ...
process will start1
child process 2 (7057) running ...
process will start3
child process 3 (7056) running ...
process will start2
child process 4 (7058) running ...
process will start4
end 0
end 1
end 2
end 3
end 4

real 0m5.099s
user 0m0.080s
sys 0m0.008s

既然是多进程，为什么process2就一定要竞争的过process3？
你这个例子中是对stdout的竞争。
因为：process2的产生在时间上，早于process3

Answer 1

既然是多进程，为什么process2就一定要竞争的过process3？
你这个例子中是对stdout的竞争。

Answer 2

多进程，是并发执行的操作，这就没什么次序可言了。主程序的for循环是非常快的，几乎瞬间5个进程就全开启了，而先启动的先输出的概率大，但并不是绝对。这就跟五个运动员在同一起跑线，即使他们起跑的时间可能会有差异，有人快一点起跑，有人慢一点起跑，但是最先到终点的就不一定是最先起跑的那个人了。