python 截取字符串

Question

com.sun.identity.agents.config.notenforced.url=[6]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[12]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[14]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[13]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[21]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[23]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[17]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[4]=http://www.abc.com

想这样的字符串，怎么截取，把前面的com.sun.identity.agents.config.notenforced.url=[*]= 去掉，只取http://www.abc.com

Answer 1

print s.split('=')[-1]

Answer 2

import re

test_str = '''com.sun.identity.agents.config.notenforced.url=[6]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[12]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[14]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[13]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[21]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[23]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[17]=http://www.abc.com
com.sun.identity.agents.config.notenforced.url=[4]=http://www.abc.com'''

print(re.findall(r'com.sun.identity.agents.config.notenforced.url=\[\d+\]=(.*)', test_str))

抛砖引玉

Answer 3

>>> s = 'com.sun.identity.agents.config.notenforced.url=[6]=http://www.abc.com'
>>> s[s.index('http'):]
'http://www.abc.com'