多个对象怎么组合成一个数组对象

Question

{
"date":{"0":"20180201","1":"20180202","2":"20180205"},
"lines":{"0":3.3,"1":10.4,"2":79.721},
"count":{"0":5,"1":21,"2":13},
"counts":{"0":5,"1":26,"2":39},
"limit":{"0":3.3,"1":13.7,"2":93.421}
}

// 最后我想变成下面这种格式，怎么弄呢
let values = [{date: '20180201', lines: 3.3,count: 5,countS: 5,limit: 3.3},{date: '20180202', lines: 10.4,count: 21,countS: 26,limit: 13.7}...];

Answer 1

const obj = {
  "date": {"0": "20180201", "1": "20180202", "2": "20180205"},
  "lines": {"0": 3.3, "1": 10.4, "2": 79.721},
  "count": {"0": 5, "1": 21, "2": 13},
  "counts": {"0": 5, "1": 26, "2": 39},
  "limit": {"0": 3.3, "1": 13.7, "2": 93.421}
};
const keys = Object.keys(obj);
const lens = Object.keys(obj[keys[0]]);
let arrays = []
for (const len of lens) {
  let o = {};
  for (const key of keys) {
    o[key] = obj[key][len];
  }
  arrays.push(o);
}
console.log(arrays);

结果：

[ { date: '20180201', lines: 3.3, count: 5, counts: 5, limit: 3.3 },
  { date: '20180202',
    lines: 10.4,
    count: 21,
    counts: 26,
    limit: 13.7 },
  { date: '20180205',
    lines: 79.721,
    count: 13,
    counts: 39,
    limit: 93.421 } ]

新需求：

const obj = {
  "v_date": {"0": "20180201", "1": "20180202", "2": "20180205", "3": "20180206", "4": "20180207", "5": "20180208"},
  "type": {"0": "现券交易", "1": "现券交易", "2": "质押式回购", "3": "质押式回购", "4": "质押式回购", "5": "现券交易"},
  "amt": {"0": 3.3, "1": 10.4, "2": 79.721, "3": 68.363, "4": 25.674, "5": 12.1},
  "num": {"0": 5, "1": 21, "2": 13, "3": 21, "4": 18, "5": 32},
  "sum_num": {"0": 5, "1": 26, "2": 13, "3": 34, "4": 52, "5": 58},
  "sum_amt": {"0": 3.3, "1": 13.7, "2": 79.721, "3": 148.084, "4": 173.758, "5": 25.8}
};
const keys = Object.keys(obj);
const lens = Object.keys(obj.type);
let types = {};
for (const t of lens) {
  if(!types[obj.type[t]]) {
    types[obj.type[t]] = [];
  }
  let o = {};
  for (const key of keys) {
    if (key !== 'type') {
      o[key] = obj[key][t]
    }
  }
  types[obj.type[t]].push(o);
}
console.log(types)

结果：

{ '现券交易': 
   [ { v_date: '20180201', amt: 3.3, num: 5, sum_num: 5, sum_amt: 3.3 },
     { v_date: '20180202',
       amt: 10.4,
       num: 21,
       sum_num: 26,
       sum_amt: 13.7 },
     { v_date: '20180208',
       amt: 12.1,
       num: 32,
       sum_num: 58,
       sum_amt: 25.8 } ],
  '质押式回购': 
   [ { v_date: '20180205',
       amt: 79.721,
       num: 13,
       sum_num: 13,
       sum_amt: 79.721 },
     { v_date: '20180206',
       amt: 68.363,
       num: 21,
       sum_num: 34,
       sum_amt: 148.084 },
     { v_date: '20180207',
       amt: 25.674,
       num: 18,
       sum_num: 52,
       sum_amt: 173.758 } ] }

当你执行console.log(Object.values(types))的时候，你会发现更多的惊喜

Answer 2

let arr = []
for(let key in obj) {
    arr.push(obj[key])
}
console.log(arr)

Answer 3

source为你最开始那个对象

for(var i =0,len=3;i<len;i++){
    values[i].date=source['date'][i];
    values[i].lines=source['lines'][i];
    ...
}

Answer 4

const oData = {
"date":{"0":"20180201","1":"20180202","2":"20180205"},
"lines":{"0":3.3,"1":10.4,"2":79.721},
"count":{"0":5,"1":21,"2":13},
"counts":{"0":5,"1":26,"2":39},
"limit":{"0":3.3,"1":13.7,"2":93.421}
},
fnData = function(o, l, a = [], i = 0) {
 for (let k in oData) {
   if (!a[i]) a[i] = {};
   a[i][k] = o[k][i];
 }
 return ++i < l && fnData(o, l, a, i) || a;
};
alert(JSON.stringify(fnData(oData, 3)));