一个4*4矩阵如何输出

Question

1 2  3  4
5 6  7  8
9 10 11 12
13 14 15 16

一个4*4的矩阵
如何顺时针由外往里输出
1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10
// 不会要套4个for把？

Answer 1

function circle(array) {
  return array.length < 2 ? array[0] : array.shift().concat(
    array.map(e=>e.pop()), 
    circle(array.map(e=>e.reverse()).reverse())
  );
}
// test
circle([[1,2,3,4],[5,6,7,8],[9,10,11,12]]);

Answer 2

function printMatrix(matrix) {
    if (matrix == null || matrix.length == 0) {
        return;
    }
    var rows = matrix.length;
    var cols = matrix[0].length;
    var start = 0;
    var result = [];

    while (cols > start * 2 && rows > start * 2) {
        var endX = cols - 1 - start;
        var endY = rows - 1 - start;
        //从左到右打印一行
        for (var i = start; i <= endX; i++) {
            result.push(matrix[start][i]);
        }
        //从上到下打印一列
        if (start < endY) {
            for (var i = start + 1; i <= endY; i++) {
                result.push(matrix[i][endX]);
            }
        }
        //从右到左打印一行
        if (start < endX && start < endY) {
            for (var i = endX - 1; i >= start; i--) {
                result.push(matrix[endY][i]);
            }
        }
        //从下到上打印一列
        if (start < endX && start < endY - 1) {
            for (var i = endY - 1; i >= start + 1; i--) {
                result.push(matrix[i][start]);
            }
        }
        start++;
    }
    return result
}

Answer 3

var test = function (matrix) {
    var x, y, border = [x = y = 0, matrix.length - 1], result = [];
    while (x <= border[1] || y <= border[1]) {
        result.push(matrix[y][x]);
        if (y == border[0] && x < border[1]) x++;
        else if (x == border[1] && y < border[1]) y++;
        else if (y == border[1] && x > border[0]) x--;
        else if (x == border[0] && y > border[0]) y--;
        if (x == border[0] && y == border[0]) {
            y = x = ++border[0];
            border[1]--;
        }
    }
    return result;
}

Answer 4

原答案

var nums = "1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16";
var arr = nums.split(',');
for(var i in arr){
  i-=0;
  if(i>0&&(i+1)%4==0){
      var str = arr.slice(i-3,i+1).join(' ');
      console.log(str)
     }
 
}

我理解错误了

Answer 5

var arr = [
[1, 2,  3,  4],
[5, 6,  7,  8],
[9, 10, 11, 12],
[13, 14, 15, 16]
]
arr.forEach(row => {
    row.forEach(n => console.log(n))
})