数组组合计算所有的组合形式?

Question

array(2) {
  [0] => array(3) {
    [0] => string(3) "16G"
    [1] => string(3) "32G"
    [2] => string(3) "64G"
  }
  [1] => array(2) {
    [0] => string(1) "L"
    [1] => string(2) "XL"
  }
}

计算所有组合
['16G','L']
['16G','XL']
['32G','L']
['32G','XL']
['64G','L']
['64G','XL']
应该怎么组合成这样的结果
array(6) {
  [0] => array(3) {
    [0] => string(3) "16G"
    [1] => string(3) "L"
  }
  [1] => array(3) {
    [0] => string(3) "16G"
    [1] => string(3) "XL"
  }
  [2] => array(3) {
    [0] => string(3) "32G"
    [1] => string(3) "L"
  }
  [3] => array(3) {
    [0] => string(3) "32G"
    [1] => string(3) "XL"
  }
  [4] => array(3) {
    [0] => string(3) "64G"
    [1] => string(3) "L"
  }
  [5] => array(3) {
    [0] => string(3) "64G"
    [1] => string(3) "XL"
  }
 }

Answer 1

把我在js版本答案里代码改成了php版如下

$input = [["16G", "32G", "64G"], ["L", "XL"]];

$output = array_reduce($input, function($result, $cross_item){
    if(!$result){
        return array_map(function($item){
            return [$item];
        }, $cross_item);
    }

    return array_reduce($cross_item, function($acc, $target) use ($result){
        return array_merge($acc, array_map(function($result_item) use ($target){
            $result_item[] = $target;

            return $result_item;
        }, $result));
    }, []);
}, []);

Answer 2

矩阵乘法 ？

算法导论之js实现--n×n矩阵计算

Answer 3

$arr = [["16G","32G","64G"],["L","XL"]];
    
$res = [];
for($i=0;$i<count($arr[0]);$i++){
    
    for($j=0;$j<count($arr[1]);$j++){
        $tem = [];
            $tem[] = $arr[0][$i];
            $tem[] = $arr[1][$j];
        
        if($tem){
    $res[] = $tem;
    }

    }
    
    
}

var_dump($res);

Answer 4

如果不需要管顺序，只需要结果，可以用位运算，来进行全组合。

var rt=[];
const arr= [["16G", "32G", "64G"], ["L", "XL"]];
for(let i=0;i<8;i++){
   let a1=i & 3;//取低2位
   if(a1>2) continue;
   let a2=i>>2;
   let t=[arr[0][a1],arr[1][a2]];
   rt.push(t);
}