关于依靠a数组筛选b数组内没有存在a数组元素

Question

A数组--tableSelectParams:["id","device_code","value"]
B数组-- "tag_columns":[{

                    "column_desc": "id",
                    "column_name": "id",
                    "isShow": true
                    },
                    {
                    "column_name": "device_code",
                    "column_desc": "设备编号",
                    "isShow": true
                    },
                    {
                    "column_name": "companyid",
                    "column_desc": "公司ID",
                    "isShow": true
                    },
                    {
                    "column_name": "addtime",
                    "column_desc": "添加时间",
                    "isShow": true
                    },
                    {
                    "column_name": "value",
                    "column_desc": "值",
                    "isShow": true
                    }
                ]

请问如何找出B数组中 column_name没有和A数组元素相同的B数组对象。
求帮忙看看。

Answer 1

let columns = tag_columns.filter(cur => !tableSelectParams.includes(cur.column_name))

Answer 2

// 生成映射表，避免过多的内循环
var map = tableSelectParams.reduce((p, c) => [p[c] = false, p][1])
var result = tag_columns.filter(i => map[i.column_name])