js 严格模式下arguments.callee用什么替代

Question

如下所示是一个定时器对象，在严格模式下会报错，有木有大佬知道怎么修改啊？

var Timing = function(fun,interval){
    this.fun = fun;
    this.interval = interval*1000;
    this.timer;
}
Timing.prototype = {
    constructor: Timing,
    setTime: function(){
        var that = this;
        var fun = that.fun;
        that.timer = setTimeout(function(){
            fun();
            that.timer = setTimeout(arguments.callee,that.interval);
        },that.interval);
    },
    clearTime: function(){
        clearTimeout(this.timer)
    }
}

实例化
var time = new Timing(function(){
    console.log('hello');
},1);
time.setTime();

控制台报错：Uncaught TypeError: 'caller', 'callee', and 'arguments' properties may not be accessed on strict mode functions or the arguments objects for calls to them

Answer 1

代替是不可能的，但是为什么要用匿名函数呢。

        that.timer = setTimeout(function cb(){
            fun();
            that.timer = setTimeout(cb,that.interval);
        },that.interval);

Answer 2

没有替代。

Answer 3

除此之外，建议学习使用 ES6 的 let 和箭头函数，代替 var 和 that。