JS 对数组的操作

Question

let a = [['1010','20','10'], ['3010','40','20']]
let b = [
{
  KUNN2:"0000000001",
  PARVW_TEXT:"收款方",
  VKORG:'3010',
  VTWEG:'40',
  VSBED:'20'
},
 {
  KUNN2:"0000000002",
  PARVW_TEXT:"收款方",
  VKORG:'1010',
  VTWEG:'20',
  VSBED:'10'
},
{
  KUNN2:"0000000003",
  PARVW_TEXT:"收款方",
  VKORG:'4100',
  VTWEG:'30',
  VSBED:'10'
},
{
  KUNN2:"0000000004",
  PARVW_TEXT:"收款方",
  VKORG:'3010',
  VTWEG:'40',
  VSBED:'20'
},
{
 KUNN2:"0000000005",
 PARVW_TEXT:"收款方",
 VKORG:'1010',
 VTWEG:'20',
 VSBED:'10'
 }
]

如上面2面2个数组，数组a是匹配项，随后我想要的结果是

let c = [[{
KUNN2:"0000000002",
PARVW_TEXT:"收款方",
VKORG:'1010',
VTWEG:'20',
VSBED:'10'
},{
KUNN2:"0000000005",
PARVW_TEXT:"收款方",
VKORG:'1010',
VTWEG:'20',
VSBED:'10'
}],[{
KUNN2:"0000000001",
PARVW_TEXT:"收款方",
VKORG:'3010',
VTWEG:'40',
VSBED:'20'
},{
KUNN2:"0000000004",
PARVW_TEXT:"收款方",
VKORG:'3010',
VTWEG:'40',
VSBED:'20'
}]]

希望各位大佬指教，不甚感激。### 题目描述

题目来源及自己的思路

相关代码

// 请把代码文本粘贴到下方（请勿用图片代替代码）

你期待的结果是什么？实际看到的错误信息又是什么？

Answer 1

应该是你想要的吧

let a = [['1010', '20', '10'], ['3010', '40', '20']]
let b = [
    {
        KUNN2: "0000000001",
        PARVW_TEXT: "收款方",
        VKORG: '3010',
        VTWEG: '40',
        VSBED: '20'
    },
    {
        KUNN2: "0000000002",
        PARVW_TEXT: "收款方",
        VKORG: '1010',
        VTWEG: '20',
        VSBED: '10'
    },
    {
        KUNN2: "0000000003",
        PARVW_TEXT: "收款方",
        VKORG: '4100',
        VTWEG: '30',
        VSBED: '10'
    },
    {
        KUNN2: "0000000004",
        PARVW_TEXT: "收款方",
        VKORG: '3010',
        VTWEG: '40',
        VSBED: '20'
    },
    {
        KUNN2: "0000000005",
        PARVW_TEXT: "收款方",
        VKORG: '1010',
        VTWEG: '20',
        VSBED: '10'
    }
]

const result = [];

for (const aItem of a) {
    const bFilter = b.filter(({ VKORG, VTWEG, VSBED }) => VKORG === aItem[0] && VTWEG === aItem[1] && VSBED === aItem[2]);
    bFilter.length > 0 && result.push(bFilter);
}
console.log(result);

Answer 2

1.你给的a数组，第一个值应该是 1010对吧，
2.a数组的值 ，我能过目测是分别与VKORG，VTWEG，VBED三个值相对应的，有没有不对应的需求，如果是对应的，哪就按下面代码来就可以

let a = [['1010','20','10'], ['3010','40','20']]
let b = [
{
  KUNN2:"0000000001",
  PARVW_TEXT:"收款方",
  VKORG:'3010',
  VTWEG:'40',
  VSBED:'20'
},
 {
  KUNN2:"0000000002",
  PARVW_TEXT:"收款方",
  VKORG:'1010',
  VTWEG:'20',
  VSBED:'10'
},
{
  KUNN2:"0000000003",
  PARVW_TEXT:"收款方",
  VKORG:'4100',
  VTWEG:'30',
  VSBED:'10'
},
{
  KUNN2:"0000000004",
  PARVW_TEXT:"收款方",
  VKORG:'3010',
  VTWEG:'40',
  VSBED:'20'
},
{
 KUNN2:"0000000005",
 PARVW_TEXT:"收款方",
 VKORG:'1010',
 VTWEG:'20',
 VSBED:'10'
 }
]

let c= b.filter((item)=>{
  let index = a.find((arr)=>{
    return arr[0]=== item.VKORG && arr[1]===item.VTWEG && arr[2]===item.VSBED
  })
  if(index){
    return item
  }
})

console.log(c)

第二种方法，判断只要obj里的值含有 数组里的值就返回，从你的回复里看到，a数组的子数组个数也不确定，但是问题 如果存在以下数据，也会被返回

{
  KUNN2:"0000000001",
  PARVW_TEXT:"收款方",
  VKORG:'10',
  VTWEG:'1010',
  VSBED:'20'
} 
用下面的方法，这样的数据也是匹配的。

let d = a.map((keys)=>{
  let res = b.filter((item)=>{
    let objarr = Object.values(item)
    let oldlength = objarr.length
    //以下代码用于判断数组是否为另一个数组的子集，采用的方法是把两个数组合并，再去重后的数组长度等于原数组长度，则判定子集匹配。
    let newarr = [...objarr,...keys]
    let newlength =[...new Set(newarr)].length
    if(oldlength === newlength){
      return item
    }
  })
  return res
  
})