请教一个正则

Question

需求：
自定义分隔符，拆分出满足下面需求的字符串。

1. 双引号内的字符串，忽略分隔符。如a,b,"c,d"拆分得到['a', 'b', '"c,d"']
2. 字符串内的单元可能包含双引号也可能不包含。如a,b,"c_d","e","f,g",h。

分隔符不一定是逗号，是自定义的，可以是空格，可以是a-z中的任意一个字符。也就是正则生成的过程大概是如下形式：

var splitBy = ','
var reg = new Reg(`...${split}...`)

可以提供一些样本字符串作为验证样本：

逗号分隔符：（半角逗号，英文的）
"rule_id","time,ti","module","dst_port","nat_src_ip","nat_src_port","nat_dst_ip","nat_dst_port","comment","src_mac","dst_mac","user","app_name","app_id","category","subcategory","risk","tags","technology","mid_session","1","1415171952","fw","G1/1","","accept","tcp","10.10.20.3","19079","10.10.14.211","1521","","","","","","00-19-B9-3D-DB-41","00-1A-A0-A9-EA-B9","","","","","","","","","1",""

空格分隔符：
a b "cc d" "s ccc" dddd cccccs

Answer 1

str.match(new RegExp(`"[^"]+"|[^${split}]+`, 'g'))