js 字符数组如何按照字符长度排序？

Question

js 字符数组如何按照字符长度排序？
有没有比较好的方法推荐，自己写了一个过于麻烦？

Answer 1

let arr = ['132','qwedd','q','2r','qwd'];
arr.sort(function(a,b){
    return a.length>b.length;
})
//输出 ["q", "2r", "132", "qwd", "qwedd"]

Answer 2

var arr = ['sdqwe1232','123','weqw123'];
console.log(arr.sort(function(a,b){
    return a.length - b.length;
}));

Answer 3

看了一下楼上的回答，每比一次都要去取一次 .length，为啥不先存一遍：

const arr = ['132','qwedd','q','2r','qwd']
const rtn = arr.map(i => ({raw: i, len: i.length}))
                .sort((p, n) => n.len - p.len)
                .map(i => i.raw)
console.log(rtn) // [ 'qwedd', '132', 'qwd', '2r', 'q' ]

---

学习了！

Answer 4

let arr = ['1234','12','4578','0986','qwerasd']
arr.sort((a, b) => {
    if (a.length > b.length) {
        return 1
    }
    if (a.length < b.length) {
        return -1
    }
    return 0
})

Answer 5

arr.forEach(s => setTimeout(console.log, s.length, s))