要实现的效果图如截图:
拿到的json类似如下代码:
chnl:[
{
"agentCode": "001",
"agentName": " 工行",
"chnllist": [
{"chnlcode": "1","chnlname": "柜面"},
{"chnlcode": "2","chnlname": "网银"},
{"chnlcode": "3","chnlname": "终端"},
{"chnlcode": "4","chnlname": "手机"}]
},
{
"agentCode": "002",
"agentName": " 农行",
"chnllist": [
{"chnlcode": "1","chnlname": "柜面"},
{"chnlcode": "2","chnlname": "网银"},
{"chnlcode": "3","chnlname": "终端"},
{"chnlcode": "4","chnlname": "手机"}]
},
{"agentCode": "003",
"agentName": " 中行",
"chnllist": [
{"chnlcode": "1","chnlname": "柜面"},
{"chnlcode": "2","chnlname": "网银"},
{"chnlcode": "3","chnlname": "终端"},
{"chnlcode": "4","chnlname": "手机"}]
},
...
]
结果成了如下的样子:
代码如下:
<div id="left_div2">
<table cellSpacing=0 cellPadding=0 id="left_table2" class="table table-bordered">
<tr v-for="agent in chnl">
<td :rowspan="agent.chnllist.length"><p>{{agent.agentName}}</p></td>
<!--<td ><p>{{agent.agentName}}</p></td>-->
<td v-for="chnel in agent.chnllist"><p>{{chnel.chnlname}}</p></td>
</tr>
</table>
</div>
**数据关系:银行包含着渠道的列表,银行的高度根据列表的长度来合并对应的行
问题:该如何处理如上json才能达到预期的效果?希望各位给个意见o((⊙﹏⊙))o**