js 数组遍历对象

Question

我想取status === "success" 这个对象里面的url，不要status === "ready"这个对象的url，用了数组forEach 和filter 都不能实现，求方法。

Answer 1

手机实在是敲不了代码 文字描述吧 用filter

return item.status===sucess
且item.url

就OK了

Answer 2

const result = arr.reduce(
  (total, cur) => (cur.status === 'success' ? [...total, cur.url] : [...total]),
  []
)

Answer 3

let urls = arr.filter(item=>item.status==="success").map(item=>item.url)

Answer 4

const arr = [{status:'success',url:'/a'},{status:'success',url:'/b'},{status:'ready',url:'/c'}];
const arr1 = arr.filter(v=>v.status!=='ready'); // [{status:'success',url:'/a'},{status:'success',url:'/b'}]
const arr2 = arr1.map(v=>v.url); // ['/a','/b']