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将所有键名为list变成children,键名为name变成label怎么弄,写了半天只改到了第二层,第三层获取的数组里都是undefined,求大神帮忙

Jone 6
2019-05-10 提问
3 个回答
3

这个tree看起来格式很规范,所以转成字符串替换下再转 JSON 得了:

JSON.parse(JSON.stringify(tree).replace(/list:/g, 'children:').replace(/name:/g, 'label:'));

从思考到写完只用不到三分钟。
而递归写起来多麻烦,你看:

const keyChange = (objTree) => {
    for(let key in objTree){
        if(objTree.hasOwnProperty(key)){
            const current = objTree[key];
            if(current instanceof Object){
                keyChange(current )
            }
            if(key === 'list'){
                objTree['children'] = current;
                delete objTree['list'];
            } else if(key === 'name'){
                objTree['label'] = current;
                delete objTree['name'];
            }
        }
    }
    return null;
}

PS. 以上代码未经测试,如有需要,请自行测试、改良。

2
function changeName(a) {
    var isArray = function(b) {
        return Object.prototype.toString.call(b) == '[object Array]';
    };
    if (isArray(a) && a.length) {
        for (let i = 0; i < a.length; i++) {
            if (a[i].name) {
                a[i].label = a[i].name;
                delete a[i].name;
            }
            if (a[i].list) {
                a[i].children = a[i].list;
                delete a[i].list;
                changeName(a[i].children);
            }
        }
    }
}

changeName(tree);
1
const tree = [
    {
        name: 'node1',
        id: '1-1'
    },
    {
        name: 'node2',
        list: [
            {
                name: 'node-2-1',
                id: '2-1'
            },
            {
                name: 'node2-2',
                id: '2-2'
            }
        ]
    },
    {
        name: 'node3',
        list: [
            {
                name: 'node-3-1',
                id: '3-1',
                list: [
                    {
                        name: 'node3-1-1',
                        id: '3-1-1'
                    }
                ]
            },
            {
                name: 'node3-2',
                id: '3-2'
            }
        ]
    }
]

function trans (tree) {
    tree.forEach(item => {
        if (item.list) {
            item.children = item.list
            delete item.list
            trans(item.children)
        }
        if (item.name !== undefined) {
            item.label = item.name
            delete item.name
        }
    })
}

trans(tree)
console.log(tree)

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