数组对象过滤属性

const selection = [
    {
        id:1,
        name:''lili',
        shopCode:'erew',
        isActice:0
    },
    {
        id:2,
        name:'dfdsaf',
        shopCode:'45425',
        isActice: 1
    },
    {
        id:3,
        name:'gfi',
        shopCode:'8yy',
        isActice: 1
    },
]

想转换为:数组对象中只保留shopCode和isActive,但是isActive之前为0变为1,为1转为0

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1 个回答
let result = selection.map(item => {
    return {
        shopCode: item.shopCode,
        isActice: item.isActice === 0 ? 1: 0 
    }
})
// result 就是你要的结果
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