element 遍历出来的select双向绑定的值怎么区分开

Question

我select是遍历出来，那怎么绑定值呢，我绑定v-model="scope.row.chooseValue"，当前行所有的框都被绑定了，请问怎么区分开，数据源它每行都有chooseValue，那我v-model="scope.row.chooseValue"应该就可以了啊，请问问题出在哪里

    <el-table-column v-for="(column, index) in columns" v-else :key="column.value" :label="column.text" :width="column.width">
        <template slot-scope="scope">
          <span v-for="space in scope.row._level" v-if="index === 0" :key="space" class="ms-tree-space"/>
          <span v-if="iconShow(index,scope.row)" class="tree-ctrl" @click="toggleExpanded(scope.$index)">
            <i v-if="!scope.row._expanded" class="el-icon-plus"/>
            <i v-else class="el-icon-minus"/>
          </span>
          <span v-if="column.text == '设备类型'">
            {{ scope.row.name }}
          </span>
            
          <el-select v-if="column.text == '周'" v-model="scope.row.chooseValue"  @change="(val)=>{fnEdit(val,scope.row.id,scope.row.chooseMode,scope.row.code,scope.row.maintenanceId)}">
              <el-option  v-for="item in week" :key="item.value" :label="item.label" :value="item.value"></el-option>
          </el-select>
        </template>
      </el-table-column>

Answer 1

用"scope.row.chooseValue[index]"