flutter StatefulWidget更新状态问题

Question

希望的效果是，被点击的cell有actived效果，其他cell去掉效果

代码如下：

import 'package:flutter/material.dart';

class MyCell extends StatefulWidget {
  final data;
  MyCell({ Key key, this.data }): super(key: key);

  _MyCellState createState() => _MyCellState();
}

class _MyCellState extends State<MyCell> {
  String _actived = '/home';

  @override
  Widget build(BuildContext context) {
    Color bg = _actived == widget.data['route'] ? Colors.grey[300] : Colors.white;
    Color co = _actived == widget.data['route'] ? Colors.pink[300] : Colors.grey[800];

    return Material(
      color: bg,
      child: InkWell(
        onTap: () {
          setState(() {
            _actived = widget.data['route'];
          });
        },
        child: Container(
          height: 50,
          padding: EdgeInsets.only(left: 20, right: 20),
          child: Row(
            crossAxisAlignment: CrossAxisAlignment.center,
            children: <Widget>[
              Icon(widget.data['icon'], color: co, size: 20,),
              Container(
                padding: EdgeInsets.only(left: 20),
                child: Text(widget.data['label'], style: TextStyle(fontSize: 16, color: co)),
              ),
            ],
          ),
        ),
      ),
    );
  }
}

Answer 1

这是drawer里单个按钮的Widget吧，每个按钮都有自己的_activated也只能被自己的点击事件重新赋值，点击其他按钮并不会影响现在这个按钮的_activated

应该把这个_activated放在drawer里会比较好，可以管理到所有按钮的state