对数组中的数据操作

Question

let ary = [{

        fileName: "文档1",
        nodeId: "1133275924701949952",
    },
    {
        fileName: "文档2",
        nodeId: "1133275743956807681",
    }, {
        fileName: "文档3",
        nodeId: "1133275683449434112",
    }, {
        fileName: "文档4",
        nodeId: "1133275743956807681",
    }, {
        fileName: "文档5",
        nodeId: "1133275683449434112",
    },
    {
        fileName: "文档6",
        nodeId: "1133275924701949952",
    }
]
 // 将相同id的文件名以“，”拼接起来，放在数组中的一项得到=>["文档1，文档6","文档2,文档4","文档3，文档5"]，怎么写啊大佬们

Answer 1

本质流程是
分组 => 映射 => 拼接

参考 https://blog.rxliuli.com/p/fc...

具体场景解决代码

Array.from(groupBy(ary, ({ nodeId }) => nodeId))
  .flatMap(([_k, v]) => v)
  .map(({ fileName }) => fileName)
  .join()

吾辈推荐解决这类问题时不要只看业务，找出其中通用的东西才更为有趣。。。

Answer 2

function transformData (ary) {
     const tempObj = ary.reduce((prev, current) => {
        prev[current.nodeId] = prev[current.nodeId] || [];
        prev[current.nodeId].push(current.fileName);
        return prev;
    },{});
    const result = [];
    for (let nodeId in tempObj) {
        const fileName = tempObj[nodeId];
        result.push(fileName.join(','));
    }
    return result;
}