将对象转换成二维数组

Question

arrStart = {a: [1,2,3,4], b: [1,2,3,4]};
转成
arrEnd = [[1,1],[2,2],[3,3],[4,4]];

Answer 1

题目有几个问题：
1.用哪两个key
2.a和b顺序没有说
3.两个长度不同的数组咋办

假定顺序先a后b吧，用数组长度较短的为准：

arrStart = {a: [1,2,3,4], b: [1,2,3,4]};
arr1 = arrStart.a;
arr2 = arrStart.b;

let c;
if (arr1.length <= arr2.length) {
    c = arr1.map(function(e, i) {
        // 先a后b
        return [e, arr2[i]];
    });
} else {
    c = arr2.map(function(e, i) {
        // 先a后b
        return [arr1[i], e];
    });
}

Answer 2

const object1 = {
  a: [1,2,3,4],
  b: [1,2,3,4]
};

let objArray=[];
for (let [key, value] of Object.entries(object1)) {
  let res = value.map((item)=>{
    return [item,item];
  })
  objArray.push(res)
}

// objArray 应该是你想要的结果

Answer 3

感谢大家，有朋友也推荐了方法

1. const main = (obj) =>

   Object.keys(obj).reduce(

   (a, key) =>
       obj[key].map((item, index) => {
       a[index] = a[index] || [];
       return a[index].concat(item);
   }),

   []

);

2.function main(value) {

let index = 1;
let arr = Object.values(value);
let result = arr[0].map(item => [item]);
return function() {
while(index < arr.length) {
    arr[index].map((item, i) => result[i].push(item));
    index++;
    }
    return result;
}

}

Answer 4

先jsonencode再jsondecode加TRUE就行了