如何过滤这个数组？

Question

`let prearr = ['1001','1002,'1003','1004'];
let nextarr = ['1002,'1003','1004','1005'];

求这个两个数组不一样的地方，最终结果 result = ['1002','1005']`

Answer 1

let prearr = ['1001', '1002', '1003', '1004'];
let nextarr = ['1002', '1003', '1004', '1005'];

const diff = (arrA, arrB) =>
  Array.from(new Set(arrA.concat(arrB))).filter(e => !(arrA.includes(e) && arrB.includes(e)));

const result = diff(prearr, nextarr);

Answer 2

let diff1 = prearr.filter(item => !nextarr.includes(item))
let diff2 = nextarr.filter(item => !prearr.includes(item))
let result = diff1.concat(diff2)

Answer 3

const result = prearr.concat(nextarr).filter(((m,n) => t => !m.has(t) || !n.has(t))(new Set(prearr), new Set(nextarr)))