正则表达提取uri?

Question

let b = 'http://www.xx.com/sd/s?s=2'
let c = b.match(/^http[s]?:\/\/(.*)\/(.*)/)

[
  'http://www.xx.com/sd/s?s=2',
  'www.xx.com/sd',
  's?s=2',
  index: 0,
  input: 'http://www.xx.com/sd/s?s=2',
  groups: undefined
]

得到这样的结果。
我这边需要的是
sd/s?s=2

请问怎么提取？

解决了： ....
match(/^http[s]?:\/\/.*\.[a-z]{2,}\/(.*)/)

Answer 1

match(/^http[s]?:\/\/.*\.[a-z]{2,}\/(.*)/)

Answer 2

            var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
            var r = window.location.search.substr(1).match(reg);
            if (r != null) return decodeURI(r[2]); return null;