数组取值问题

Question

data 数组如下,只有id和name不同.
想取出tableAliasName的值.多条记录,值是相同的.

如果用map,输出还是一个2个对象的数组.

现在是用: data.[0].tableAliasName 取的.

是否有其它方法?

data:

[
  {
    "aliasName": "car_type",
    "id": "0799b1e8-bf5d-45f8-81b0-7f1b50a42791",
    "isAggregation": false,
    "name": "car_type",
    "orderInfo": "NONE",
    "tableAliasName": "6666",
    "type": "VARCHAR",
    "nodeId": "6047d731"
  },
  {
    "aliasName": "car_id",
    "id": "2d5bbc42-fb4e-473c-8ab0-3fc46c77109a",
    "isAggregation": false,
    "name": "car_id",
    "orderInfo": "NONE",
    "tableAliasName": "6666",
    "type": "VARCHAR",
    "nodeId": "6047d731"
  }
]

Answer 1

你是想要去重？

Answer 2

Object.keys(data.reduce((acc, item) => {acc[item.tableAliasName] = 1; return acc;}, {}))

Answer 3

data[0].tableAliasName 没毛病啊，我也这么写；

要么就在这数组外边单独返回一个字段。