try...except 语句里，执行完 except 怎么回去执行 try ？

Question

def doSth():
    ...
    
try:
    doSth()
except:
    print("requests speed so high,need sleep!")
    time.sleep(10)
    print("continue...")
    #这行要加什么才能再回去执行上面的try？

while True:
     doSth()
     time.sleep(120)

try...except 语句里执行完 except， 怎么回去执行 try ？

Answer 1

你其实都已经想到用 while 了, 再往前进一步即可

以下是一个带最大重试次数的反复请求代码

# -*- coding: utf8 -*-
import time
import random

def dosomething():
    # 只有 1/3 随机概率执行到 print("hello")
    if random.randint(1, 3) == 3:
        print ("hello")
    else:
        raise Exception("unknown error")

def request_with_retry(max_times):
    times = 0
    while times <= max_times:
        times += 1
        try:
            dosomething()
            break
        except:
            time.sleep(1)
            print ("retry, times: %s/%s" % (times, max_times))
            
if __name__ == '__main__':
    request_with_retry(5)

Answer 2

def loop():
    times = 0
    while True:
        try:
            do_something()
            return
        except:
            times +=1
            # 如果尝试次数达到10次就跳出循环
        if times == 10:
            print("尝试次数过多，失败")
            return

Answer 3

你需要的可能不是try except,而是with ... as