js for循环删除指定下标对象

Question

0: {amount: 1, giftMoney: 0,  price: 12, money: 12, …}
1: {amount: 1, giftMoney: 0,  price: 100, money: 100, …}
2: {amount: 1, giftMoney: 0, price: 100, money: 100, …}

假设我要删除第1个，并且拿到删除后的对象，那应该怎么操作呢

在这里先先谢谢各位大哥大姐的解答了，感谢！

完整的是这样的：

var obj =
[{amount: 1, giftMoney: 0, price: 12, money: 12}
{amount: 1, giftMoney: 0, price: 100, money: 100}
{amount: 1, giftMoney: 0, price: 100, money: 100}]

Answer 1

是这样吗？

var array = new Array();
var obj1 = {amount: 1, giftMoney: 0, price: 12, money: 12};
var obj2 = {amount: 1, giftMoney: 0,  price: 100, money: 100};
var obj3 = {amount: 1, giftMoney: 0,  price: 200, money: 200};
array.push(obj1);
array.push(obj2);
array.push(obj3);
for (var i = 0;i < array.length; i++){
   if (i == 1){
       array.splice(i,1);
   }
}
console.log(array);

新的代码：

var obj = [{amount: 1, giftMoney: 0, price: 12, money: 12},
{amount: 1, giftMoney: 0, price: 100, money: 100},
{amount: 1, giftMoney: 0, price: 200, money: 200},]
for (var i = 0;i < obj.length; i++){
   if (i == 1){
       obj.splice(i,1);
   }
}
console.log(obj);

运行结果:

> Array [Object { amount: 1, giftMoney: 0, price: 12, money: 12 }, Object { amount: 1, giftMoney: 0, price: 200, money: 200 }]

Answer 2

arr.splice(0, 1)

Answer 3

let arr = arr.splice(0, 1) // 获取被删除返回后的数组aar
let data = arr.splice(0, 1)[0]// 获取被删除返回后数组第0个成员数据