请问这样的API返回结果我使用PHP该怎么获得其中的数据?

Question

因为我需要获取这个API的返回结果,写入数据库中.但是因为我是小白.不会取josn中需要的值,请各位大佬帮忙!
接口地址:https://api.oioweb.cn/api/ran...
返回结果:1. {

1. "code": 1,
2. "msg": "查询成功！",
3. "data": {
4. "360": {
5. "img": "https://statics.aizhan.com/images/360/10.png",
6. "weight": "10"
7. },
8. "br": {
9. "img": "https://statics.aizhan.com/images/br/10.png",
10. "weight": "10"
11. },
12. "mbr": {
13. "img": "https://statics.aizhan.com/images/mbr/10.png",
14. "weight": "10"
15. },
16. "sr": {
17. "img": "https://statics.aizhan.com/images/sr/10.png",
18. "weight": "10"
19. },
20. "msr": {
21. "img": "https://statics.aizhan.com/images/msr/10.png",
22. "weight": "10"
23. },
24. "m360": {
25. "img": "https://statics.aizhan.com/images/m360/10.png",
26. "weight": "10"
27. },
28. "sm": {
29. "img": "https://statics.aizhan.com/images/sm/8.png",
30. "weight": "8"
31. }
32. }
33. }

我需要新建一个PHP文件获取其中的360、br、mbr、sr、msr、m360、sm中的weight显示的值。
这样该怎么写。谢谢！

Answer 1

<?php
$url = '这里填写你的url';
// 注意. 建议你用curl来请求. 我这里只是为了图快.
$response_json = file_get_contents($url);
$response = @json_decode($response_json, true);

if(!$response || $response['code'] != 1) {
    exit(0);
} 

$channels = [];

foreach($response['data'] as $channel => $info) {
    $channels[$channel] = $info['weight'];
}

var_dump($channels);
var_dump($channels['mbr']);

未经过任何测试的代码，具体逻辑就是这个样子.

Answer 2

用PHP cURL去请求API，然后拿到返回结果按照楼上说的处理