如何快速获取数组中最后一条记录中的某个值

Question

[{"index":0,"url":"/uploads/20210515/77224f5334636205c823f9ff455c848f.xlsx"},{"index":1,"url":"/uploads/20210515/aa85a3e19c174d7bb0ed8be23ad535e6.jpg"},{"index":2,"url":"/uploads/20210515/83f6ab0c5710c32966962d3e71d0c2e3.doc"}]

想快速获取数组中最后一条记录中的url值，这个数组可能3条也可能有8条记录

Answer 1

const arr = [{"index":0,"url":"/uploads/20210515/77224f5334636205c823f9ff455c848f.xlsx"},{"index":1,"url":"/uploads/20210515/aa85a3e19c174d7bb0ed8be23ad535e6.jpg"},{"index":2,"url":"/uploads/20210515/83f6ab0c5710c32966962d3e71d0c2e3.doc"}]

const lastUrl = arr[arr.length-1].url

Answer 2

根据你描述
const last = temp[temp.length-1].url
temp.pop().url 方法用于删除并返回数组的最后一个元素。
temp.slice(-1).url

Answer 3

arr[arr.length - 1].url
//以后可以用
arr.at(-1).url