python threading.local调用问题

Question

a.py里创建了thread_local = threading.local()
然后a.py调用b.py或c.py的函数。
b.py或c.py，不通过传参数，怎么输出thread_local值？
代码如下：
a.py

import threading
from concurrent.futures import ThreadPoolExecutor

from b import print_txt


def task():
    thread_local.test = 'test'
    print_txt()


thread_local = threading.local()
max_workers = 2
with ThreadPoolExecutor(max_workers=max_workers, ) as executor:
    for i in range(2):
        future = executor.submit(task)

b.py

def print_txt():
    # 怎么输出thread_local.test的值
    pass

Answer 1

在b.py里给print_txt函数加个参数，在里面用print打印这个参数。
然后在a.py的task里print_txt（thread_local.test）