const arr = [
{
id:1,
date:[['2021-06-17 00:00','2021-06-30 23:59'],['2021-07-18 00:00','2021-08-18 23:59']],
name:'a',
},
{
id:1,
date:[['2021-05-20 00:00','2021-06-11 23:59'],['2021-07-18 00:00','2021-08-18 23:59']],
name:'a',
},
{
id:2,
date:[['2021-06-14 00:00','2021-06-25 23:59'],['2021-10-18 00:00','2021-12-18 23:59']],
name:'a',
},
{
id:2,
date:[['2021-06-01 00:00','2021-06-25 23:59'],['2021-06-18 00:00','2021-12-18 23:59']],
name:'b',
},
]
//筛选出arr数组中id不同,name相同,date存在交集的元素
如题!
我目前是用reduce两两相比,里面的date再去双重循环做比较,不知道还有没有更优的解法呢
试试 dayjs diff方法,或者看看源码找找思路