在线求一个正则表达式【急】

Question

匹配@到空格的内容，然后把内容替换为div包裹@内容，类似下面这样，但是不能把后面的@www匹配进去，因为@www后面是没有空格的

"adaskjdkas @mushroom kalsdkl@www" -> "adaskjdkas <div>@mushroom</div> kalsdkl@www"

我之前用的正则是这样的a.replace(/(@[^\s+]+)/g, '<span>$1</span>')，但是会把@www匹配进去

在线求助/(ㄒoㄒ)/~~

Answer 1

a.replace(/(@[^]+\s{1,})/g, '<span>$1</span>')

Answer 2

a.replace(/(@[^\s+]+\s)/g, '<span>$1</span>')

Answer 3

var a = "adaskjdkas @mushroom kalsdkl@www";
a.replace(/\@(.+?)\b[^$]/g, '<span>$1</span>')
"adaskjdkas <span>mushroom</span>kalsdkl@www"

Answer 4

"adaskjdkas @mushroom kalsdkl@www".replace(/\@([^\s]+?)(?=\s)/g, '<span>$1</span>') 
// "adaskjdkas <span>mushroom</span> kalsdkl@www"