这种数组在element中怎么合并列，数据是动态的

Question

var arr2 = [
    {
      id: 1,
      name:"张三",
      sector: "测试组",
      value:111,
      totalfee: 60,
      cost: 25,
      starttime: '2021',
      endtime: "2021-10-11",
      reason: "测试1"
    },
    {
      id: 1,
      name:"张三",
      sector: "测试组",
      value:111,
      totalfee: 60,
      cost: 35,
      starttime: '2021',
      endtime: "2021-10-22",
      reason: "测试2"
    },
    {
      id: 2,
      name:"李四",
      sector: "前端组",
      value:222,
      totalfee: 150,
      cost: 10,
      starttime: '2021',
      endtime: "2021-10-11",
      reason: "测试1"
    },
    {
      id: 2,
      name:"李四",
      sector: "前端组",
      value:222,
      totalfee: 150,
      cost: 20,
      starttime: '2021',
      endtime: "2021-10-12",
      reason: "测试2"
    },
    {
      id: 2,
      name:"李四",
      sector: "前端组",
      value:222,
      totalfee: 150,
      cost: 50,
      starttime: '2021',
      endtime: "2021-10-13",
      reason: "测试4"
    },
    {
      id: 2,
      name:"李四",
      sector: "前端组",
      value:222,
      totalfee: 150,
      cost: 70,
      starttime: '2021',
      endtime: "2021-10-14",
      reason: "测试3"
    },
  ];

table 部分

<el-table
      :data="Newteble"
      v-loading.body="listLoading"
      :element-loading-text="listLoadText"
      border
      fit
      highlight-current-row
      id="printTest"
      :span-method="objectSpanMethod"
    >
      <el-table-column align="center" label="ID">
        <template slot-scope="scope">{{scope.row.id}}</template>
      </el-table-column>
      <el-table-column align="center" label="部门">
        <template slot-scope="scope">{{scope.row.sector}}</template>
      </el-table-column>
      <el-table-column align="center" label="姓名">
        <template slot-scope="scope">{{scope.row.name}}</template>
      </el-table-column>
      <el-table-column align="center" label="加班餐补费总额">
        <template slot-scope="scope">{{scope.row.totalfee}}</template>
      </el-table-column>
      <el-table-column align="center" label="加班详情">
        <el-table-column align="center" label="开始时间">
          <template slot-scope="scope">{{scope.row.starttime}}</template>
        </el-table-column>
        <el-table-column align="center" label="结束时间">
          <template slot-scope="scope">{{scope.row.endtime}}</template>
        </el-table-column>
        <el-table-column align="center" label="金额">
          <template slot-scope="scope">{{scope.row.cost}}</template>
        </el-table-column>
        <el-table-column align="center" label="具体详情">
          <template slot-scope="scope">{{scope.row.reason}}</template>
        </el-table-column>
      </el-table-column>
    </el-table>

vue中方法部分不知道改怎么动态合并,如下

objectSpanMethod({ row, column, rowIndex, columnIndex }) {
      // if (columnIndex === 0) {    //用于设置要合并的列
      //   if (rowIndex % 2 === 0) {   //用于设置合并开始的行号
      //     return {
      //       rowspan: 2,　　　　　//合并的行数
      //       colspan: 1          //合并的列数，设为０则直接不显示
      //     };
      //   } else {
      //     return {
      //       rowspan: 0,
      //       colspan: 0
      //     };
      //   }
      // }

      

    },

目前视图

想要下面这种

Answer 1

可以对数据进行判断，定义数组来记录要合并的索引，第一条不合并，之后每一条，如果跟上一条一样，就进行记录，然后在colspan值处进行判断

实现代码https://codesandbox.io/s/zen-...

Answer 2

官网示例
elementui也有合并行/列的例子，从上面链接点进去往下翻可以看见，倒数第二个例子。

Answer 3

https://blog.csdn.net/qq_2946...