两个数组合并

Question

a:[
    {
        name: "a",
        value: 0
    },
    {
        name: "b",
        value: 1
    },
    {
        name: "c",
        value: 2
    }
]
b:[11,22,33]

想合并成

a:[
    {
        name: "a",
        value: 0,
        id :11,
    },
    {
        name: "b",
        value: 1,
        id :22,

    },
    {
        name: "c",
        value: 2,
        id :33

    }
]

Answer 1

根据序列设置

var obj = {a:[
    {
        name: "a",
        value: 0
    },
    {
        name: "b",
        value: 1
    },
    {
        name: "c",
        value: 2
    }
],
b:[11,22,33]};

obj.b.map((id,idx)=>{
return {id,...obj.a[idx]};
})

Answer 2

function transform(obj) {
    var b = obj.b;
    delete obj.b;
    for (var i = 0; i < obj.a.length; ++i) obj.a[i].id = b[i];
    return obj;
}
var obj = {
    a: [{
        name: "a",
        value: 0
    },
    {
        name: "b",
        value: 1
    },
    {
        name: "c",
        value: 2
    }],
    b: [11, 22, 33]
};
console.log(transform(obj));

Answer 3

let obj={
    a:[{name: "a",value: 0},{name: "b",value: 1},{name: "c",value: 2}],
    b:[11,22,33]
}                
obj.a.forEach((item,index)=>{
    item.id=obj.b[index];
})
console.log(obj.a);

Answer 4

var a = [
    {
        name: "a",
        value: 0
    },
    {
        name: "b",
        value: 1
    },
    {
        name: "c",
        value: 2
    }
]
var b = [11,22,33]

var newArr = a.map((item,index) => item.id = b[item.value]);
console.log(newArr);

Answer 5

let arr1 = [
{
  name: "a",
  value: 0
},
{
  name: "b",
  value: 1
},
{
  name: "c",
  value: 2
}
  ]
  let arr2 = [11,22,33]
  let newArr = arr1.map((item, index) => {
  item.id = arr2[index]
  return item
})
console.log(newArr)