遍历一个json对象,向下查找conditionNodes条件子节点,如果不存在,则开始遍历childNode,取得type=1的所有审核人信息,保留原结构方便查找上一级的审核人信息
Json数据结构大致如下:
{
"nodeName": "发起人",
"type": 0,
"id": "_8c697987-f88e-43b0-b67f-36cc3530e06a",
"childNode": {
"id": "_7dd20c08-e177-4ddd-8481-7fefcf4fa6e2",
"nodeName": "审批人",
"type": 1,
"childNode": {
"id": "_4e9d8722-33be-4073-80aa-ceca6599f263",
"nodeName": "条件分支",
"type": 4,
"conditionNodes": [
{
"id": "_16c48673-fe23-4e15-842e-a4a5f738e03e",
"nodeName": "条件1",
"type": 3,
"childNode": {
"id": "_ad137e80-8965-4cd3-a4bb-3ef3d4cf6f9c",
"nodeName": "机器人",
"type": 2,
"childNode": {
"id": "_a1d518b7-aa18-41b3-81a3-0e7e1d2a8cde",
"nodeName": "审批人",
"type": 1,
"childNode": null
}
}
},
{
"id": "_61f38c80-5d4b-49fd-bf4e-341f25b5a59d",
"nodeName": "条件2",
"type": 3,
"childNode": {
"id": "_6de1ace1-6454-426d-ada0-b1e57cb6d361",
"nodeName": "机器人",
"type": 2,
"childNode": {
"id": "_5d2b4876-e7ba-43d6-95b4-fe93a74d4120",
"nodeName": "审批人",
"type": 1,
"childNode": null
}
}
}
],
"childNode": {
"id": "_4d0590c1-e501-4da6-af9a-adceeea05be1",
"nodeName": "审批人",
"type": 1,
"childNode": {
"id": "_2b283452-426f-46b1-8b7a-00650ab71d37",
"nodeName": "结束节点",
"type": 5
}
}
}
}
}
为了实现流程回退的效果,需要取得所有的审核人节点信息,然后从中查找出当前审核人的上一个审核人信息,为了保留原有的结构信息,有了思路,但是不知道怎么写