_October has a question:
You are given n integers a1,a2,…,an. Find the maximum value of max(al,al+1,…,ar)⋅min(al,al+1,…,ar)over all pairs (l,r) of integers for which 1≤l<r≤n.
INPUT:
The first line contains a single integer n(2≤n≤10的3次方) .
The second line contains n integers a1,a2,…,an(1≤ai≤10的6次方).
OUTPUT:
Please print a single integer — the maximum possible value of the product from the statement.
SAMPLE INPUT1:
3
2 4 3
SAMPLE OUTPUT1:
12
Note:
Let f(l,r)=max(al,al+1,…,ar)⋅min(al,al+1,…,ar). In the first test case, f(1,2)=max(a1,a2)⋅min(a1,a2)=max(2,4)⋅min(2,4)=4⋅2=8. f(1,3)=max(a1,a2,a3)⋅min(a1,a2,a3)=max(2,4,3)⋅min(2,4,3)=4⋅2=8. f(2,3)=max(a2,a3)⋅min(a2,a3)=max(4,3)⋅min(4,3)=4⋅3=12. So the maximum is f(2,3)=12.
SAMPLE INPUT2:
4
3 2 3 1
SAMPLE OUTPUT2:
6
Advanced challenge :What if the maxinum of n is 3∗10的5次方 ?
中文说就是输入一组数,函数f(l,r)的值是其中一个子区间[l,r]的最大值乘最小值,求最大的f(l,r)