js 如何把内存循环里面的字段提出来拼接外层循环的字段,来个大佬解决哈！求！

Question

原始数据： obj1

  obj1: {
        beginFlag: false,
        checkUserCode: "1043",
        consumableFiledNum: 0,
        id: "",
        stockRegisterDetailList: [{
          batch: "1",
          checkStatus: true,
          contractCode: null,
          sourceCodeList: [
            {
              originalCode: 1001,
              checkStatus: 1,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由1111'
            },
            {
              originalCode: 1002,
              checkStatus: 0,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由222'
            }, {
              originalCode: 1003,
              checkStatus: 0,
              rejectionProcessType: 2,
              rejectionDescription: '退货理由333'
            }
          ]
        },
        {
          batch: "2",
          checkStatus: true,
          contractCode: 222,
          sourceCodeList: [
            {
              originalCode: 100111,
              checkStatus: 1,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由1111'
            },
            {
              originalCode: 100222,
              checkStatus: 0,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由222'
            }
          ]
        },
        ]
      },

理想数据： obj2

   obj2: {
        beginFlag: false,
        checkUserCode: "1043",
        consumableFiledNum: 0,
        id: "",
        stockRegisterDetailList: [
          {
            originalCode: 1001,
            checkStatus: 1,
            rejectionProcessType: 1,
            rejectionDescription: '退货理由1111',
            batch: "1",
            checkStatus: true,
            contractCode: null,
          },
          {
            batch: "1",
            checkStatus: true,
            contractCode: null,
            originalCode: 1002,
            checkStatus: 0,
            rejectionProcessType: 1,
            rejectionDescription: '退货理由222'
          },
          {
            batch: "1",
            checkStatus: true,
            contractCode: null,
            originalCode: 1003,
            checkStatus: 0,
            rejectionProcessType: 2,
            rejectionDescription: '退货理由333'
          },
          {
            batch: "2",
            checkStatus: true,
            contractCode: 222,
            originalCode: 100111,
            checkStatus: 1,
            rejectionProcessType: 1,
            rejectionDescription: '退货理由1111'
          },
          {
            batch: "2",
            checkStatus: true,
            contractCode: 222,
            originalCode: 100222,
            checkStatus: 0,
            rejectionProcessType: 1,
            rejectionDescription: '退货理由222'
          },
        ]
      },

Answer 1

  obj1= {
        beginFlag: false,
        checkUserCode: "1043",
        consumableFiledNum: 0,
        id: "",
        stockRegisterDetailList: [{
          batch: "1",
          checkStatus: true,
          contractCode: null,
          sourceCodeList: [
            {
              originalCode: 1001,
              checkStatus: 1,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由1111'
            },
            {
              originalCode: 1002,
              checkStatus: 0,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由222'
            }, {
              originalCode: 1003,
              checkStatus: 0,
              rejectionProcessType: 2,
              rejectionDescription: '退货理由333'
            }
          ]
        },
        {
          batch: "2",
          checkStatus: true,
          contractCode: 222,
          sourceCodeList: [
            {
              originalCode: 100111,
              checkStatus: 1,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由1111'
            },
            {
              originalCode: 100222,
              checkStatus: 0,
              rejectionProcessType: 1,
              rejectionDescription: '退货理由222'
            }
          ]
        },
        ]
      }

obj1.stockRegisterDetailList = obj1.stockRegisterDetailList.map(v=>v.sourceCodeList.map(v1=>({...v,...v1}))).flat()
obj1

Answer 2

你想要的数据结构有问题，stockRegisterDetailList里的项有个键checkStatus重复了。
这里的实现以子级的值为准。

const obj2 = {
    ...obj1,
    stockRegisterDetailList: obj1
        .stockRegisterDetailList
        .flatMap(({ sourceCodeList, ...parent }) =>
            sourceCodeList.map(child => ({ ...parent, ...child })),
        ),
};