数组对象排序、多条件排序如何实现？

Question

let arr = [
    {playerid: 1, score: 120, time: '00:24', count: 24},
    {playerid: 2, score: 110, time: '00:16', count: 16},
    {playerid: 3, score: 120, time: '00:24', count: 23},
    {playerid: 4, score: 105, time: '00:15', count: 16},
    {playerid: 4, score: 105, time: '00:18', count: 13}
]

先根据 score 降序排序，score 值相同的时候再以 count 降序排序
得到结果如下，求一方法

let arr = [
    {playerid: 1, score: 120, time: '00:24', count: 24},
    {playerid: 3, score: 120, time: '00:24', count: 23},
    {playerid: 2, score: 110, time: '00:16', count: 16},
    {playerid: 4, score: 105, time: '00:15', count: 16},
    {playerid: 4, score: 105, time: '00:18', count: 13}
]

Answer 1

一行代码搞定~

let arr = [
    {playerid: 1, score: 120, time: '00:24', count: 24},
    {playerid: 2, score: 110, time: '00:16', count: 16},
    {playerid: 3, score: 120, time: '00:24', count: 23},
    {playerid: 4, score: 105, time: '00:15', count: 16},
    {playerid: 4, score: 105, time: '00:18', count: 13}
];

arr.sort((a, b) => b.score === a.score ? b.count - a.count : b.score - a.score);

console.log(arr);

Answer 2

arr.sort((x, y) => y.score - x.score || y.count - x.count) 

听说有人写得比我简洁，这是不可以的。