这段代码可以简化吗？

Question

不想用循环

const path = require("path");
const os = require("os");
let localhost;
try {
  const network = os.networkInterfaces();
  for (let i in network) {
    for (let j in network[i]) {
      const val = network[i][j];
      if (val.family === "IPv4" && val.address !== "127.0.0.1") {
        localhost = val.address;
        break;
      }
    }
  }
} catch (e) {
  localhost = "http://localhost";
}

Answer 1

一句话解决：

localhost = Object
    .values(network)
    .flat()
    .find(it => it.family === "IPv4" && it.address !== "127.0.0.1")
    ?.address

另外，我记得 family 的取值是 4 或 6，没有 "IPv4" 吧？