我有一个mysql问题。
我的网站上有一个新闻部分,我想显示两个最新项目。如果我做:
SELECT * FROM nieuws ORDER BY id DESC LIMIT 1
它选择了最新的项目,现在我想选择倒数第二个项目。
你们知道怎么做吗?
/// 编辑
现在它不起作用,这是我的代码:(我已连接包括在内;))
$select = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMIT 1");
while($row = mysql_fetch_assoc($select)) {
$datum = $row['time'];
$titel = $row['title'];
$bericht = $row['message'];
?>
<div class="entry">
<span class="blue date"><?php echo "$datum"; ?></span>
<h3><?php echo "$titel"; ?></h3>
<p><?php echo "$bericht"; ?></p> <br />
</div><!-- end of entry --> <?php } ?>
<?php
$select2 = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMI 1, 1");
while($row2 = mysql_fetch_assoc($select2)) {
$datum = $row2['time'];
$titel = $row2['title'];
$bericht = $row2['message'];
?>
<div class="entry">
<span class="green date"><?php echo "$datum"; ?> </span>
<h3><?php echo "$titel"; ?></h3>
<p><?php echo "$bericht"; ?></p>
</div> <!-- end of entry --> <?php } ?>
</div><!-- end of news -->
原文由 Andre 发布,翻译遵循 CC BY-SA 4.0 许可协议
SELECT * FROM nieuws ORDER BY id DESC LIMIT 2
- 选择最后 2 项SELECT * FROM nieuws ORDER BY id DESC LIMIT 1, 1
- 仅选择第二项