检查密码的强度（如何检查条件）

Question

我正在尝试创建一个需要您输入密码的系统。如果全部为 lower、upper 或 num，则打印 weak，如果是其中两个条件，则为 med，如果全部满足则为 strong。它似乎不起作用。

弱者和强者起作用，而媒介则不起作用。

我不知道我哪里出错了。

 def password():

    print ('enter password')
    print ()
    print ()
    print ('the password must be at least 6, and no more than 12 characters long')
    print ()

    password = input ('type your password    ....')

    weak = 'weak'
    med = 'medium'
    strong = 'strong'

    if len(password) >12:
        print ('password is too long It must be between 6 and 12 characters')

    elif len(password) <6:
        print ('password is too short It must be between 6 and 12 characters')

    elif len(password)    >=6 and len(password) <= 12:
        print ('password ok')

        if password.lower()== password or password.upper()==password or password.isalnum()==password:
            print ('password is', weak)

        elif password.lower()== password and password.upper()==password or password.isalnum()==password:
            print ('password is', med)

        else:
            password.lower()== password and password.upper()==password and password.isalnum()==password
            print ('password is', strong)

原文由 user2412839 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

你好

最好的方法是使用正则表达式搜索

这是我目前正在使用的功能

def password_check(password):
    """
    Verify the strength of 'password'
    Returns a dict indicating the wrong criteria
    A password is considered strong if:
        8 characters length or more
        1 digit or more
        1 symbol or more
        1 uppercase letter or more
        1 lowercase letter or more
    """

    # calculating the length
    length_error = len(password) < 8

    # searching for digits
    digit_error = re.search(r"\d", password) is None

    # searching for uppercase
    uppercase_error = re.search(r"[A-Z]", password) is None

    # searching for lowercase
    lowercase_error = re.search(r"[a-z]", password) is None

    # searching for symbols
    symbol_error = re.search(r"[ !#$%&'()*+,-./[\\\]^_`{|}~"+r'"]', password) is None

    # overall result
    password_ok = not ( length_error or digit_error or uppercase_error or lowercase_error or symbol_error )

    return {
        'password_ok' : password_ok,
        'length_error' : length_error,
        'digit_error' : digit_error,
        'uppercase_error' : uppercase_error,
        'lowercase_error' : lowercase_error,
        'symbol_error' : symbol_error,
    }

编辑：

在这里接受 Lukasz 的建议是对特殊符号条件验证的更新

symbol_error = re.search(r"\W", password) is None

原文由 ePi272314 发布，翻译遵循 CC BY-SA 3.0 许可协议