我有一个问题,我必须计算 Python (v3.4.1) 中的重复单词并将它们放在一个句子中。我使用了计数器,但我不知道如何按以下顺序获取输出。输入是:
mysentence = As far as the laws of mathematics refer to reality they are not certain as far as they are certain they do not refer to reality
我把它做成一个列表并对其进行了排序
输出应该是这样的
"As" is repeated 1 time.
"are" is repeated 2 times.
"as" is repeated 3 times.
"certain" is repeated 2 times.
"do" is repeated 1 time.
"far" is repeated 2 times.
"laws" is repeated 1 time.
"mathematics" is repeated 1 time.
"not" is repeated 2 times.
"of" is repeated 1 time.
"reality" is repeated 2 times.
"refer" is repeated 2 times.
"the" is repeated 1 time.
"they" is repeated 3 times.
"to" is repeated 2 times.
到目前为止我已经到了这一点
x=input ('Enter your sentence :')
y=x.split()
y.sort()
for y in sorted(y):
print (y)
原文由 Erwy Lionel 发布,翻译遵循 CC BY-SA 4.0 许可协议
我可以通过排序看到您的去向,因为您可以可靠地知道何时击中了一个新词并跟踪每个唯一词的计数。但是,您真正想要做的是使用散列(字典)来跟踪计数,因为字典键是唯一的。例如:
现在这将为您提供一本字典,其中键是单词,值是它出现的次数。您可以使用
collections.defaultdict(int)
做一些事情,因此您只需添加值:但甚至还有比这更好的东西……
collections.Counter
它将把你的单词列表变成一个包含计数的字典(实际上是字典的扩展)。从那里您需要按计数排序的单词列表,以便您可以打印它们。
items()
将为您提供一个元组列表,并且sorted
将(默认情况下)按每个元组的第一项(在本例中为单词)排序…这正是你要。输出