我目前正在尝试使用库 PyMySQL 通过 python 程序连接到我在 AWS 上创建的 MySql 数据库
# !/usr/bin/env python
# -*- coding: utf-8 -*-
import pymysql
host = 'admin.cjp8hsqu4je0.us-east-2.rds.amazonaws.com'
user = 'admin'
password = '12345678'
database = 'admin'
connection = pymysql.connect(host, user, password, database)
with connection:
cur = connection.cursor()
cur.execute("SELECT VERSION()")
version = cur.fetchone()
print("Database version: {} ".format(version[0]))
当我运行上面的代码时,出现以下错误:
Traceback (most recent call last):
File "C:\Users\SuperPC\AppData\Local\Programs\Python\Python38-32\lib\site-packages\pymysql\connections.py", line 581, in connect
sock = socket.create_connection(
File "C:\Users\SuperPC\AppData\Local\Programs\Python\Python38-32\lib\socket.py", line 808, in create_connection
raise err
File "C:\Users\SuperPC\AppData\Local\Programs\Python\Python38-32\lib\socket.py", line 796, in create_connection
sock.connect(sa)
socket.timeout: timed out
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "bot.py", line 10, in <module>
connection = pymysql.connect(host, user, password, database)
File "C:\Users\SuperPC\AppData\Local\Programs\Python\Python38-32\lib\site-packages\pymysql__init__.py", line 94, in Connect
return Connection(*args, **kwargs)
File "C:\Users\SuperPC\AppData\Local\Programs\Python\Python38-32\lib\site-packages\pymysql\connections.py", line 325, in __init__
self.connect()
File "C:\Users\SuperPC\AppData\Local\Programs\Python\Python38-32\lib\site-packages\pymysql\connections.py", line 630, in connect
raise exc
pymysql.err.OperationalError: (2003, "Can't connect to MySQL server on 'admin.cjp8hsqu4je0.us-east-2.rds.amazonaws.com' (timed out)")
我究竟做错了什么?我给函数的参数是正确的。会不会是MySql驱动的问题?
原文由 Keriger 发布,翻译遵循 CC BY-SA 4.0 许可协议
如果您想通过互联网从 AWS 外部访问您的 RDS,则应将其设置为 公开可用:
它还应该放置在 公共子网 中(例如默认 VPC)并在其安全组中打开入站规则( 好的做法 是 限制 对选定 IP 或 IP 范围的访问,而不是使用
0.0.0.0/0
):希望这可以帮助。