在python套接字编程中建立连接后如何获取客户端的IP地址？

Question

我编写了一个套接字程序来发送文件并从套接字中接收一个字符串，其中我指定了客户端（写了客户端的 ip 地址）我想动态获取该客户端地址，我尝试了 .getpeername() 函数但出现错误

我尝试了 .getpeername() 函数但出现错误

#host = '10.66.227.181'   # fixed ip of one client only
client_socket = socket.socket()
host = client_socket.getpeername()
print(clientip)
port = 8000
print(host,port)
client_socket.connect(host,port)

clientip = socket.gethostname(client_socket.getpeername()) OSError: [WinError 10057] 不允许发送或接收数据的请求，因为套接字未连接并且（当使用 sendto 调用在数据报套接字上发送时）未提供地址

原文由 Lucifer 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

如果未连接 UDP 套接字，则没有对等体。所以不可能有对等名称。如果它已连接，您已经知道如何连接它。

 client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client_socket.connect(host,port)
host, port = client_socket.getpeername()

原文由 Free Code 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 2

这是“Python 网络编程基础”一书中关于 udp 套接字（服务器端和客户端）的示例，我认为这个示例对您很有用：

 import argparse, socket
from datetime import datetime

MAX_BYTES = 65535

def server(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    sock.bind(('127.0.0.1', port))
    print('Listening at {}'.format(sock.getsockname()))
    while True:
        data, address = sock.recvfrom(MAX_BYTES)
        text = data.decode('ascii')
        print('The client at {} says {!r}'.format(address, text))
        text = 'Your data was {} bytes long'.format(len(data))
        data = text.encode('ascii')
        sock.sendto(data, address)

def client(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    text = 'The time is {}'.format(datetime.now())
    data = text.encode('ascii')
    sock.sendto(data, ('127.0.0.1', port))
    print('The OS assigned me the address {}'.format(sock.getsockname()))
    data, address = sock.recvfrom(MAX_BYTES)  # Danger! See Chapter 2
    text = data.decode('ascii')
    print('The server {} replied {!r}'.format(address, text))

if __name__ == '__main__':
    choices = {'client': client, 'server': server}
    parser = argparse.ArgumentParser(description='Send and receive UDP locally')
    parser.add_argument('role', choices=choices, help='which role to play')
    parser.add_argument('-p', metavar='PORT', type=int, default=1060,
                        help='UDP port (default 1060)')
    args = parser.parse_args()
    function = choices[args.role]
    function(args.p)

资源

原文由 EntGriff 发布，翻译遵循 CC BY-SA 4.0 许可协议