这是我的代码:
应用程序.py
from flask_graphql import GraphQLView
from app.infrastructure.graphql import schema
from app.infrastructure.api_resource import app
app.add_url_rule('/graphql', view_func=GraphQLView.as_view('graphql', schema=schema, graphiql=True))
if __name__ == '__main__':
app.run(debug=True)
api_resource.py
import app.infrastructure.repository as repository
from flask import request, url_for
from flask_restplus import Api, Resource, fields
from sqlalchemy_pagination import paginate
from sqlalchemy_fulltext import FullTextSearch
app = repository.app
api = Api(app, version='0.1', title='xxxxx',
description='xxxxx')
...
存储库.py
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from app.domain.model import Base
connection_string = 'xxxxxx'
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = connection_string
app.config['SQLALCHEMY_ECHO'] = True
db = SQLAlchemy(app, metadata=Base.metadata)
但是,当我执行 gunicorn 命令“gunicorn app: app”时,出现此错误:
> Failed to find application object 'app' in 'app' > > ``` 我在 ubuntu 16.04 上使用 pipenv whith pipenv shell,但我也尝试了一个 docker 容器并得到了同样的错误。这是我的 pip 文件:
[[source]] url = “https://pypi.python.org/simple” verify_ssl = true name = “pypi”
[dev-packages]
[packages] flask-graphql = “” flask-sqlalchemy = “” sqlalchemy-fulltext-search = “” graphene-sqlalchemy = “>=2.0” flask-marshmallow = “” sqlalchemy-pagination = “” flask-restplus = “” requests = “” mysqlclient = “” gunicorn = “*”
[requires] python_version = “3.6”
”`
我究竟做错了什么?
原文由 jhonatan teixeira 发布,翻译遵循 CC BY-SA 4.0 许可协议
您有一个名为
app
的文件夹(如文件中的导入行所示)和一个app.py
文件。Gunicorn 将尝试在
app
模块中找到app
WSGI 变量,在您的情况下,它被标识为app/__init__.py
您需要重命名文件夹或
app.py
文件以避免此冲突。